we need some assumptions before solving this question: applying mechanical energy balance between point 1 and point 2 we get $$\frac g{g_c}\bigtriangleup z+F=0$$ for water $$ยต=1.0\times10^{-3}kg/ms$$ $$\rho=1000kg/m^3$$ For pipe entrance K factor , $$K_f=\frac{160}{Re}+0.50$$ For gate valve, $$K_f=\frac{300}{Re}+0.10$$ For pipe exit, $$K_f=1.0$$ for pipe length, $$K_f=\frac{4fL}d=\frac{4f\times33}{0.10}=1320f$$ adding all K factors we get $$\sum K_f=\frac{460}{Re}+1320f+1.60$$ for…
Category: Chemical Plant Operations and Safety
this subject deals with various aspects of chemical processes,equipments,safety in industrial operations.students can learn about hazard identification,mitigation and safety protocols.
Determine the TLV for a uniform mixture of dusts containing the following particles:Nonasbestiform talc and Quartz with concentration 70,30 and TLV 20,2.7 respectively
given : Type of dust Concentration(wt.%) TLV(mppcf) Nonasbestiform talc 70 20 Quartz 30 2.7 we will use the following formula : $$TLV=\frac1{{\displaystyle\frac{C_1}{TLV_1}}+{\displaystyle\frac{C_2}{TLV_2}}}$$ $$TLV=\frac1{{\displaystyle\frac{0.70}{20}}+{\displaystyle\frac{0.30}{2.7}}}$$ =6.8
Determine the 8hr TWA worker exposure if the worker is exposed to toulene vapours as follows:duration of exposure are 3,3,4 and measured concentration are 100,250,90 respectively.TLV for toulene is 100ppm.is the worker overexposed ?
the following shows simple method to solve this question given: Duration of Exposure(hr) Measured Concentration(ppm) 3 100 3 250 4 90 we can use the equation $$\frac{C_1T_1+C_2T_2+C_3T_3}{T_1+T_2+T_3}$$ on putting the values we get $$\frac{100\ast3+250\ast3+90\ast4}{3+3+4}$$ =141